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计算.(1)5.2-(负3/4)+(+5/6)-(负7/12)(2)+3又8/11的绝对值-10/27的绝对值-9/11的绝对值+负9/5的绝对值=?
题目内容:
计算.(1)5.2-(负3/4)+(+5/6)-(负7/12) (2)+3又8/11的绝对值-10/27的绝对值-9/11的绝对值+
负9/5的绝对值=?优质解答
解(1)
原式=26/5+3/4+5/6+7/12
=26/5+9/12+10/12+7/12
=26/5+13/6
=156/30+65/30
=221/30
解(2)
原式=3又8/11-10/27-9/11+9/5
=41/11-10/27-9/11+9/5
=(41/11-9/11)+9/5-10/27
=32/11+9/5-10/27
=4320/1485+2673/1485-550/1485
=4又503/1485 - 追问:
- 我打错了,第二个式子应该是3又8/11-10/27-19/11+9/5
- 追答:
- 你好: 3又8/11-10/27-19/11+9/5 =(3又8/11-19/11)-10/27+9/5 =(41/11-19/11)-10/27+9/5 =2-10/27+9/5 =44/27+9/5 =220/135+243/135 =463/135
负9/5的绝对值=?
优质解答
原式=26/5+3/4+5/6+7/12
=26/5+9/12+10/12+7/12
=26/5+13/6
=156/30+65/30
=221/30
解(2)
原式=3又8/11-10/27-9/11+9/5
=41/11-10/27-9/11+9/5
=(41/11-9/11)+9/5-10/27
=32/11+9/5-10/27
=4320/1485+2673/1485-550/1485
=4又503/1485
- 追问:
- 我打错了,第二个式子应该是3又8/11-10/27-19/11+9/5
- 追答:
- 你好: 3又8/11-10/27-19/11+9/5 =(3又8/11-19/11)-10/27+9/5 =(41/11-19/11)-10/27+9/5 =2-10/27+9/5 =44/27+9/5 =220/135+243/135 =463/135
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