题目内容：

计算:2(3+1)(3的2次幂+1)(3的4次幂+1)……(3的16次幂+1)+1
麻烦写下过程

优质解答

2*(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)+1
=(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)+1
=(3^2-1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)+1
=(3^4-1)(3^4+1)(3^8+1)(3^16+1)+1
.
=(3^16-1)(3^16+1)+1
=3^32-1+1
=3^32