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(999..9)1999个9加1999...9(1999个9)的平方根怎样算?求求你们!
题目内容:
(999..9)1999个9加1999...9(1999个9)的平方根怎样算?
求求你们!优质解答
999...9(1999个9)*999...9(1999个9)+1999...9(1999个9)
=999...9^2(1999个9)+1999...98(1999-1个9)+1
=999...9^2(1999个9)+2*999...9(1999个9)*1+1^2
=(999...9(1999个9)+1)^2
=1000...0^2(1999个0)
=1000...0(2*1999个0)
求求你们!
优质解答
=999...9^2(1999个9)+1999...98(1999-1个9)+1
=999...9^2(1999个9)+2*999...9(1999个9)*1+1^2
=(999...9(1999个9)+1)^2
=1000...0^2(1999个0)
=1000...0(2*1999个0)
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