题目内容：

f(x)=x(x-1)(x-2)(x-3)则f‘（0）=多少?

优质解答

f(x)=x(x-1)(x-2)(x-3)
f'(x)=(x-1)(x-2)(x-3)+x[(x-1)(x-2)(x-3)]'
f'(0)=(-1)*(-2)*(-3)+0
=-6