题目内容：

已知2x-3y=1,求4的2x次方乘8的2y次方分之3减一的值

优质解答

4^2x*3/8^2y-1
=(2^2)^2x*3/(2^3)^2y-1
=2^4x*3/2^6y-1
=3*2^(4x-6y)-1
=3*2^[2(2x-3y)]-1
=3*2^0-1
=3-1
=2