题目内容：

解两道方程题；1/2[x-1/2(x+1)]=2/3 (x-1) 1/3(x-1)+1/4(x-1)-1/2(x-1)=1

优质解答

1/2[x-1/2(x+1)]=2/3 (x-1)1/2[x-1/2x-1/2)]=2/3 (x-1)1/4[x-1]=2/3 (x-1)1/4[x-1]-2/3 (x-1)=0(1/4-2/3)[x-1]=0x-1=0x=11/3(x-1)+1/4(x-1)-1/2(x-1)=1(1/3+1/4-1/2)(x-1)=11/12 (x-1)=1x-1=12x=13