题目内容：

分解因式(2X²-3X+1)²-22X²+33X-1 （x+y-2XY)(x+y-2)+(xy-1)^2

优质解答

a=2x²-3x+111a=22x²-33x+11所以原式=a²-11a+10=(a-1)(a-10)=(2x²-3x+1-1)(2x²-3x+1-10)=x(2x-3)(2x+3)(x-3)（x+y-2XY)(x+y-2)+(xy-1)^2=[（x+y)-2xy][(x+y)-2]+(xy-1)²=(x+y)²-2...