首页 > 中学考试杂题 > 题目详情

已知数列{an}满足a1=1,an-an+1=anan+1,数列{an}的前n项和为Sn. (1)求证:数列为等差数列; (2)设Tn=S2n-Sn,求证:Tn+1>Tn.

本题链接: