题目内容：

1/2a+1/2b+1/2c>或=1/(b+c)+1/(a+b)+1/(a+c)

优质解答

(a-b)²≥0(a+b)²≥4ab1/4a+1/4b =(a+b)/4ab ≥(a+b)/(a+b)²1/4a+1/4b≥1/(a+b) (1)同理 1/4a+1/4c≥1/(a+c) (2)1/4b+1/4c≥1/(b+c) (3)(1)+(2)+(3)得1/2a+1/2b+1/2c≥1/（b+c）+1/（c＋a）+1/（a＋b...