O,A,B是平面三点.直线AB上有C,满足向量2AC+向量CB=0求向量OC.A.2OA-OBB.-OA+2OBC.2/3OA-1/3OBD.-1/3OA+2/3OB
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题目内容：
O,A,B是平面三点.直线AB上有C,满足向量2AC+向量CB=0
求向量OC.
A.2OA-OB
B.-OA+2OB
C.2/3OA-1/3OB
D.-1/3OA+2/3OB
优质解答
OC =OA+AC
OC=OB+BC
==> OC = 2(OA+AC)－(OB+BC)= 2OA－OB ＋ 2AC＋CB＝2OA－OB
选 A
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